This is also the most efficient algorithm too, nice work!

detectHand(int[] hand)

//Do the first half of a counting sort
int[] countedHand = new int[13]
for each card in hand
countedHand[hand]++

//Go through each element in the counted array
boolean foundThree=false
boolean foundTwo=false
for each count in countedHand
if( count == 4)
return “Four of a kind”
else if( (foundThree && count == 2) || (foundTwo && count == 3) )
return “Full house”
else if( foundTwo && count == 2 )
return “Two of a kind”
else if( count == 3 )
foundTwo = false
else if( count == 2 )
foundTwo = true
end
end
if(foundThree)
return “Three of a kind”
else if(foundTwo)
return “Pair”
else
return “High Card”
end
end